Thejollyhellhound20
25.08.2019 •
Mathematics
What is the approximate volume of the cone with a height of 9 cm and a radius of 15 cm.
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Ответ:
V = (1/3) pi (15)^2 * 9
V = 675 pi
V = 2120,575 square cm (approx)
Ответ:
Volume of emerald = 137.04cm³
Step-by-step explanation:
Given that:
Mass of emerald = 378.24grams
Density of emerald = 2.76grams/cm³
Volume = ?
The equation for this relationship is ρ = m / V in which ρ is density, m is mass (kg or g) and V is volume (cm³ or m³) making the density unit kg/m³ or g/cm³.
Therefore
Density = mass/volume
Volume = Mass/density
i.e
Volume of emerald = Mass of emerald / Density of emerald
Volume of emerald = 378.24grams / 2.76grams/cm³
Volume of emerald = 137.043cm³ ~137.04cm³
Volume of emerald =137.04cm³