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lcidsjay
08.07.2019 •
Mathematics
What is the equation in point-slope form for the line parallel to y = -2x + 10 that contains j(6, 8)? a. y - 8 = -2(x - 6) b. x - 8 = 2(y - 6) c. y - 8 = 2(x - 6) d. y + 8 = -2(x - 6)
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Ответ:
Hello mate!
A linear equation has the form y = ax + b
where x is the variable, a is the slope and b is the x-intercept.
We want to find the pararel line to y = -2x + 10
A paralel line of this, will be another line with the same slope ( -2 in this case) and a different x-intercept; then our line has the shape of:
y = -2x + b
and we know that this line pases through the point (6,8), and with this info we could find the value of b:
8 = -2*6 + b
b = 8 + 12 = 20
then y = -2x + 20 is the pararel line that passes through the point (6.8)
Then the correct answer is the option a:
a) y - 8 = -2(x - 6) = -2x + 12
y = -2x + 12 + 8 = -2x + 20
Ответ:
answer:
a. temperature, time, length
b. temperature, dollars, length
c. height, dollars, width
d. height, time, width
step-by-step explanation: