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Isaiahtate053
04.07.2020 •
Mathematics
What is the equation, in slope-intercept form, of the line that is perpendicular to the line y-4= -2/3 (x-6) and passes through the point (-2, -2)?
Oy=-2/3x-10
Oy=-2/3x+10
Oy=x3/2x-1
O y=3/2x+1
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Ответ:
The answer is option D.
Equation of a line is y = mx + c
m = slope
c = intercept on y axis
y-4= -2/3 (x-6)
y = -2/3x + 4 + 4
y = -2/3x + 8
From the above equation
m= -2/3
Since the lines are perpendicular the slope of the line is the negative inverse of the original line.
so m = 3/2
Equation of the line using point (-2 , -2) is
y + 2 = 3/2(x+2)
y = 3/2x + 3 - 2
y = 3/2x + 1
That's the last option
Hope this helps
Ответ:
moderate negative correlation