anahitrejo1
20.10.2020 •
Mathematics
What is the equation of a line passing through the point (4,-1) and parallel to the line whose equation is 2y-x=8
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Ответ:
9514 1404 393
2y -x = -6
Step-by-step explanation:
You can use the same x- and y-coefficients. You just have to change the constant on the right. Put the point values into the left expression to see the new constant.
2y -x = 2(-1)-(4) = -6
The parallel line is ...
2y -x = -6
Ответ:
63,94,41,71
Step-by-step explanation:
63+94+41+71=270