wolfsaway
31.10.2019 •
Mathematics
What is the equation of a line that passes through the point (6, 1) and is perpendicular to the line whose equation is y=−2x−6 ?
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Ответ:
y=1/2x-2
Step-by-step explanation:
y=-2x-6
slope = -2x
reciprocal slope = I/2x
equation of line = y-y1=m(x-x1)
y-1=1/2(x-6)
y-1=1/2x-3
y=1/2x-2
Ответ: