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peno211
12.02.2021 •
Mathematics
What is the equation of the line that is perpendicular to y=1/5x+4 and that passes through (5,—4)?
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Ответ:
Work Shown:
The given equation y = (1/5)x+4 is in the form y = mx+b with m = 1/5 as the slope.
Apply the negative reciprocal to this slope to go from 1/5 to -5/1 or -5.
The original slope is 1/5 and the perpendicular slope is -5. Note the two slopes multiply to -1. This applies to any pair of perpendicular lines as long as neither line is vertical.
We'll use m = -5 as the slope and (x,y) = (5,-4) to find the y intercept
y = mx+b
-4 = -5*5+b
-4 = -25+b
-4+25 = b
21 = b
b = 21
The y intercept of the perpendicular line is b = 21
With m = -5 and b = 21, we go from y = mx+b to y = -5x+21 which is the equation of the perpendicular line.
Ответ: