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yukichaniscool8
18.01.2020 •
Mathematics
What is the rate of change of the angle of elevationin(rad/sec)when the balloon is 40m above the ground ?
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Ответ:
given
dh/dt=4m/sec
we get
tan(x)=h/40
where x is the angle and h is the height
take the derivitive of both sides
1/cos²(x)(x)dx/dt=
1/cos²(x)dx/dt=
1/cos²(x)dx/dt=
solve for dx/dt
times both sides by cos²(x)
dx/dt=
remember that dh/dt=4
also, solve for the angle at that time
h=40 and base=40 so x=45 degrees (pi/4 radians)
input that
dx/dt=
dx/dt=
dx/dt=0.05
A is the answer
Ответ:
answer:
32
step-by-step explanation:
you can do 5+27 which equals 35 so then u have ur anwser