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minaale
14.07.2019 •
Mathematics
What is the remainder rrr when the polynomial p(x)p(x)p, left parenthesis, x, right parenthesis is divided by (x++4)? left parenthesis, x, plus, 4, right parenthesis, question mark \qquad p(x) = -3x^3-10x^2+5x-12p(x)=−3x 3 −10x 2 +5x−12?
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Ответ:
We can use synthetic division to divide
by (x+4).
So, divisor will be x+4=0
Hence, x+4-4=0-4
x=-4.
Next step is to write all the coefficient and the constant in order. I am attaching the synthetic division method in a file by using the following stpes.
Step 1: Carry down the first leading coefficient 3.
Step 2: Multiply this coefficient 3 with the divisor -4 which will reslu (-3)*(-4)= 12.
Step 3: Place this 12 in the second colum and then add.
Hence, repeat this method till the constant .
At the last place we will get the remainder which is 0.
So, remainder is 0.
Ответ:
x=9
Step-by-step explanation: