What is the solution set of (x^2+x-6/x-7)< _0

X^2 + x - 6 
   <=  0
  x - 7 

(x + 3)(x - 2)
<= 0
    x - 7

2 critical values are  x = -3 and x = 2

if x <= -3  the  the function <= 0  so that's one part of the solution
also x >= 2
x must be < 7  if its = 7 then the function is indeterminate.  and values between 2 and 7 will give negative valu to function

The answer is  choice A.

It is basically the expanded form it is 1

Step-by-step explanation: