kids2006
30.06.2019 •
Mathematics
What is the solution to the equation? a. h=11/3b.h=5c.h=21/2d. h=7
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Ответ:
D. h=7
Step-by-step explanation:
1 2 16
+ =
h-5 h+5 (h^2 -25)
1 2 16
+ =
h-5 h+5 (h-5)(h+5)
Since h^2 -25 factors in (h-5) (h+5) ( it is the difference of squares)
We will multiply both sides by (h-5) (h+5) to clear the fractions
(h-5) (h+5) 2 (h-5) (h+5) 16 (h-5) (h+5)
+ =
h-5 h+5 (h-5)(h+5)
Canceling like terms
(h+5) 2 (h-5) 16
+ =
1 1 1
h+5 + 2(h-5) = 16
Distribute
h+5 + 2h -10 = 16
Combine like terms
3h-5=16
Add 5 to each side
3h-5+5 =16+5
3h =21
Divide each side by 3
3h/3 = 21/3
h = 7
Ответ:
the like terms are - q and (3/7)q
Step-by-step explanation:
3.6 p minus q minus 4 + StartFraction r over 3 EndFraction + StartFraction 3 over 7 EndFraction q = 3.6p - q- 4 + r/3 + (3/7)q
The like terms are the terms with same letters, alphabet .
For the above expression, the like terms are -q and (3/7)q
All others do not have a like term.