What is the solutions of the quadratic equation?

x2 = 9x + 6

Hello : 
note : 
the discriminat of each quadratic equation : ax²+bx+c=0 (a ≠ 0) is :
Δ = b² -4ac
1 )  Δ > 0  the equation has two reals solutions : x =  (-b±√Δ)/2a
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ < 0 : no reals solutions
in this exercice : 
x² = 9x+6
x² -9x -6 = 0
Δ = b² - 4ac    ... a =1      b = -9   c  =-6
Δ = (-9)² -4(1)(-6)=105
He continued...

Just copying this over just in case others with similar questions turn this up in search results rather than the other, haha!
When you multiply or divide a negative by another negative, you get a positive. When it is a negative and a positive, it remains negative.
Assuming your question simplified into a equation (or number form? Been a while, haha!) is 32÷-2÷(-16÷4), it would end as a positive. Because you first divide the positive 32 by a negative 2, you get a negative. Because -16÷4 is in parenthesis, it is done because following the rest of the equation (P.E.M.D.A.S.!), it would be 32÷-2÷-4. Going from left to right, as you should, it results in a negative being divided by another negative, so you get a positive. 32÷-2÷(-16÷4) = 32÷-2÷-4 = -16÷-4 = 2!