quayakaty

17.02.2020 •

Mathematics

What is the square root of 53 between two numbers to the tenth place

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Ответ:

Emorej22

12.12.2020

Mathematics

Option A is correct

$3(\frac{x}{4})-\frac{1}{2}(\frac{x}{10})$

Step-by-step explanation:

Given that:

70% of x.

⇒ $\frac{70}{100} \times x$

⇒ $\frac{7x}{10}$

Option A:

$3(\frac{x}{4})-\frac{1}{2}(\frac{x}{10})$

⇒ $\frac{3x}{4}-\frac{x}{20}$

⇒ $\frac{60x-4x}{80}$

⇒ $\frac{56x}{80}$

Simplify:

⇒ $\frac{7x}{10}$

Option B:

$3(\frac{x}{4})-(\frac{x}{10})$

⇒ $\frac{3x}{4}-\frac{x}{10}$

⇒ $\frac{30x-4x}{40}$

⇒ $\frac{26x}{40}$

Simplify:

⇒ $\frac{13x}{20}$

Option C:

$(\frac{x}{2})+(\frac{x}{10})$

⇒ $\frac{6x}{10}$

Simplify:

⇒ $\frac{3x}{5}$

Option D:

$(\frac{x}{2})+\frac{1}{2}(\frac{x}{4})$

⇒ $\frac{x}{2}+\frac{x}{8}$

⇒ $\frac{5x}{8}$

Therefore, only option which is equivalent to 70% of x is, Option A i.e $3(\frac{x}{4})-\frac{1}{2}(\frac{x}{10})$

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