What is the sum of the first five terms in a geometric sequence with a1 = 6 and r=1/3

To solve this problem you must apply the proccedure shown below:
 1. You have that a1=6 and r=1/3, therefore you must apply the following formula:
 Sn=a(1-r^n)/1-r
 2. When you substitute the values shown above, you obtain:
 S5=6(1-(1/3)^5)/(1-(1/3))
 S5=242/27
 Therefore, the answer is 242/27

y=-20,:x=-2

PLEASE MARK BRAINLIEST