What is the total perimeter of the pitch and seating area? what is the total area of the pitch and seating area?

The total Perimeter of the pitch and seating area is 179.83 m an the Total Area is 1394 m²

Step-by-step explanation:

Figure is attached with required naming.

Length of the Rectangle 1 = 40 m

width of the Rectangle 2 = 2000 cm = 20 m

radius of semi circle 2 =

radius of semi circle 3 =

length of the rectangle 4 = 25 m

width of the rectangle 4 = 800 cm = 8 m

length of the rectangle 5 = 10 m

width of the rectangle 5 = 800 cm = 8 m

Total Perimeter of the pitch and seating area

= length of rectangle 1 + circumference of semi circle 2 + circumference of semi circle 3 + length of rectangle 4 + 2 × width of rectangle 4 + length of rectangle 5 + 2 × width of the rectangle 5 + (length of rectangle 1 - length of rectangle 4 - length of he rectangle 5)

= 40 + π(10) + π(10) + 25 + 2 × 8 + 10 + 2 × 8 + ( 45 - 25 -10 )

= 40 + π(10) + π(10) + 25 + 16 + 10 + 16 + 10

= 117 + 20π

= 179.83 m (approx.)

Total area of the pitch and seating area

= Area of the Rectangle 1 + Area of semi circle 2 + area of semi circle 3 + area of rectangle 4 + area of rectangle 5

= 40 × 20 + π(10)² + 25 × 8 + 10 × 8

= 800 + 100π + 200 + 80

= 1080 + 314

= 1394 m²

Therefore, The total Perimeter of the pitch and seating area is 179.83 m an the Total Area is 1394 m²

1m = 100 cm

so
40 m = 4,000 cm
25 m = 2,500 cm
10 m = 1,000 cm

perimeter of big rectangle = 2(4,000 + 2000) = 12,000 cm
perimeter of small rectangle on the left: 2(2,500 + 800) = 6,600 cm
perimeter of small rectangle on the right: 2(1,000 + 800) = 3,600 cm
perimeter of circle = πd = 3.141593 x 200 = 628.32 cm

total area of the pitch and seating area :
=  12,000 + 6,600 + 3,600 + 628.32 = 22,828.32 cm

answer
22,828.32 cm

The diagonal is 39.54 in

Step-by-step explanation:

First we use the Pythagorean theorem to calculate the length of the diagonal of the base.

If the base measures 13 inches by 35 inches then the diagonal is:

Now we use the Pythagorean theorem again to find the diagonal of the cube.

If the height of the box is 13 inches and the diagonal of the base is 37.34 inches then the diagonal of the cube will be

The baton will fit in the box if it is placed in the direction of the diagonal of the cube, since:

39.54\ in > 38 inches