Mathematics: What s the equation of the line that s a perpendicular bisector of the segment connecting A (–2, 8) and B (–4, 2)? Question 12 options: A) y = –1∕3x – 3 B) y = –1∕3x + 3 C) y = 1∕3x + 3 D) y = –1∕3x + 4

The first odd is 1/5 and the second odd is 1/9...

What s the equation of the line that s a perpendicular

Ответ:

jlperez77

27.01.2022

Mathematics

Step-by-step explanation:

The required line is perpendicular bi sector. So it goes through the midpoint of AB. Find the midpoint of AB

Midpoint $(\frac{x_{1}+x_{2}}{2} , \frac{y_{1}+y_{2}}{2})\\$

Midpoint of AB = $(\frac{-2 + [-4]}{2} , \frac{8+2}{2})$

$=(\frac{-6}{2} , \frac{10}{2})\\\\=(-3 , 5)$

Find the slope of AB, $m_{1}$

slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\$

$=\frac{2 - 8}{-4-[-2]}\\\\=\frac{-6}{-4+2}\\\\=\frac{-6}{-2}\\\\=3$

Slope of the perpendicular line to AB = $\frac{-1}{m_{1}}$ = -1/3

The required line passes through (-3, 5) and has slope -1/3

Equation of required line : y - y1 = m (x -x1)

$y - 5 = \frac{-1}{3} (x - [-3])\\\\y-5=\frac{-1}{3} ( x +3)\\\\y-5=\frac{-1}{3}x + 3 *\frac{-1}{3}\\\\y-5=\frac{-1}{3}x-1\\\\y=\frac{-1}{3}x-1+5\\\\y=\frac{-1}{3}x + 4$

0,0(0 оценок)

What's the equation of the line that's a perpendicular bisector of the segment connecting A (–2, 8) and B (–4, 2)?
Question 12 options:

A)

y = –1∕3x – 3

B)

y = –1∕3x + 3

C)

y = 1∕3x + 3

D)

y = –1∕3x + 4

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question

What's the equation of the line that's a perpendicular bisector of the segment connecting A (–2, 8) and B (–4, 2)? Question 12 options: A) y = –1∕3x – 3 B) y = –1∕3x + 3 C) y = 1∕3x + 3 D) y = –1∕3x + 4

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question

What's the equation of the line that's a perpendicular bisector of the segment connecting A (–2, 8) and B (–4, 2)?
Question 12 options:

A)

y = –1∕3x – 3

B)

y = –1∕3x + 3

C)

y = 1∕3x + 3

D)

y = –1∕3x + 4