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foreignking02
28.09.2019 •
Mathematics
What's the solution for x-5y=1 and 2x-7y=8
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Ответ:
x-5y=1
+5y +5y
x=5y+1
Now lets fine y:
2x-7y=8
/2x /2x
-7y=4x
/-7 /-7
y=-4x
7
Ответ:
Fist thing you should know ANY NUMBER WHICH IS TO POWER ZERO THE ANSWER WILL ALWAYS BE ONE!!
Part A : (7^2)^x is (49)^x
(49)^x = 1 , here is basically asking you what’s the value of X to know which number to the power of 49 to put so that it equals to 1, obviously the answer is 0 as we said before ANY NUMBER TO THE POWER OF 0 , the answer will be 1
Part A = 0
————————-
Part B IS GONNA BE WAY EASIER NOW TRUST ME!!
(7^0) = 1
(1)^x = 1
So now is asking what number to put for x for you to multiply by one to get one it’s obviously 1, because 1 x 1= 1
Part B = 1
————-
I hope you understand my explanation so good luck and best of wishes!!