What should be the value of the standard deviation? like what's a good standard deviation?

for an approximate answer, estimate your coefficient of variation (cv=standard deviation / mean).as a rule of thumb, a cv > = 1 indicates a relatively high variation, while a cv < 1 can be considered low. this means that distributions with a coefficient of variation higher than 1 are considered to be high variance whereas those with a cv lower than 1 are considered to be low-variance.

remember,   standard deviations aren't "good" or "bad". they are indicators of how spread out your data is. a "good" sd depends if you expect your distribution to be centered or spread out around the mean. this really depends on your data.

step-by-step explanation:

Verena because AB is perpendicular on BC

Step-by-step explanation:

first need to find the length of each side :

AB=Distance between two points =

√(xB-xA)^2+((yB-yA)^2=√(4-2)^2+(4-0)^2=√20=2√5

BC do the same =d = √(xb - xc)^2 + (yb - yc)^2 =√5

CB the same (base) : d = √(xc - xb)^2 + (yc - yb)^2 =√5

AC=d = √(xa - xc)^2 + (ya - yc)^2 =√25=5

find the slope of the line to see if the two lines are perpendicular the slope has to be negative reciprocal

for BC the slope is m=y2-y1/x2-x1=-1/2

for AC the slope is 3/4

for AB and BC the slope

AB slope  m=2

BC slope -1/2

AB is perpendicular on BC