Whats the m.a.d. of 0, 3, 6, 9, 11, 13, 14? n=7

4 2/7

Step-by-step explanation:

It is convenient to let a spreadsheet or graphing calculator do the tedious math for you. (See the attachment.)

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The sum of the numbers is 56, so their average is 56/7 = 8. Then the absolute deviations from average are ...

... 8, 5, 2, 1, 3, 5, 6

and the total of these is 30. The mean absolute deviation is this sum divided by the number of numbers, 7, so is ...

... 30/7 = 4 2/7

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More about Absolute Deviation from Average

"Absolute" here refers to the absolute value function, which drops the sign of a negative number. The absolute deviation of the data value 0 is ...

... |0 - 8| = |-8| = 8

For 3, it is ...

... |3 - 8| = |-5| = 5

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

Step-by-step explanation:

The function N(t) = 800 t -  5t², represents the number of cars produced at a time t hours in a day, where 0 ≤ t ≤ 10

The function C(N) = 30,000 + 8,000 N, represents the cost C (in dollars) of producing N cars

We need to find The cost C as a function of the time t

That means Substitute N in C by its function by other word find the composite function (C о N)(t)

∵ C(N) = 30,000 + 8,000 N

∵ N(t) = 800 t - 5 t²

- Substitute N in C by 800 t - 5 t²

∴ C(N(t)) = 30,000 + 8000(800 t - 5 t²)

- Multiply the bracket by 8000

∴ C(N(t)) = 30,000 + 8000(800 t) - 8000(5 t²)

∴ C(N(t)) = 30,000 + 6,400,000 t - 40,000 t²

- C(N(t) = C(t)

∴ C(t) = 30,000 + 6,400,000 t - 40,000 t²

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²