WHEN Activy Telling Time
Law Our Weis
war's Do This Way Sare for the lopaed Time incans the amouesome
between two give une Write voor our
Mathematics notebook Numbet done for you
Acthy The
Latihan
Let This
1 Shaniel went to the beach at 10:00 AM and stayed for six hours
What did he leave the beach at 4.00 PM
2. Oave wait for a run Helena 600 and ran 12 miesitheran miles each
how at what time did stop running?
Tema
The started logging at 8:30 He logged for 1 hour and 45 minute. What
Ume did ha rah jogging?
annons
4 What is the time, one hour and 15 minutes ans 7007
1
rote to the
2. This det
5. Lovely started reading a novel at 1 00 PM on read for three hours and 20
minutes. What time did she finish reading the book?
4 Deg Fahrenhet
5. Temperatures in
6. The
6. Jenicho drew a portra for 8 hours and 30 minutes and Inished a 10.30​

Given:

Probability that the Yankees wins a game is

P(A) = 0.46

Probability that the Yankees loses a game is

P(A') = 1 - P(A') = 1 - 0.46 = 0.54

Probability that the Yankees scores 5 or more runs in a game is

P(B) = 0.59

Probability that the Yankees scores fewer than 5 runs in a game is

P(B') = 1 - P(B) = 1 - 0.59 = 0.41

Probability that the Yankees wins and scores 5 or more runs is

P(A⋂B) = 0.39

Applying the De Morgan's law, the probability that the Yankees scores fewer than 5 runs and they loses the game would satisfy:

1 - P(A'⋂B') = P(A) ⋃ P(B) = P(A) + P(B) - P(A⋂B)

or

1 - P(A'⋂B') = 0.46 + 0.59 - 0.39

or

1 - P(A'⋂B') = 0.66

=> P(A'⋂B') = 1 - 0.66 = 0.34

Applying the Bayes theorem, the probability that the Yankees would score fewer than 5 runs, given they lose the game:

P(B'|A')  = P(A'⋂B')/P(A')

or

P(B'|A') = 0.34/0.54 = 0.630

Hope this helps!

:)