Which calculation will ALWAYS have a result greater than 1? CLEAR CHECK 89 × a number less than 1 112 – a fraction less than 12 25 + a fraction less than 12 10 × a number less than 1

112 – a fraction less than 12

Step-by-step explanation:

We need to look for only one value that will invalidate the claim.

We denote the unknown in the condition with .

Let's consider each individually:

1. 89 × a number less than 1

We only need values that satisfy this inequality to invalidate the claim. Like 0, -1,...

2. 112 - a fraction less than 12

But this is a contradiction because must be less than 12.

Hence, this is always true.

3. 25 + a fraction less than 12

Hence, all fractions less than or equal to will invalidate the claim. Like -24, -25,...

4. 10 × a number less than 1

We only need values that satisfy this inequality to invalidate the claim. Like 0, -1,...

The solution is (2 , -1)

Step-by-step explanation:

* You have two ways to solve the system of equations

1. Elimination method:

By making the coefficients of one of the two variables equal in the 2

equations in magnitude and different in sign to eliminate it and find the

other variable

2. Substitution method:

By finding one of the two variables in terms of the other in one of the

two equations and substitute this value in the second equation

* Lets solve our system using the elimination method

∵ 6x + 7y = 5 ⇒ (1)

∵ 2x - 3y = 7 ⇒ (2)

- Multiply equation (2) by -3 to eliminate x

∵ (-3)(2x) - (-3)(3y) = (-3)(7)

∴ -6x + 9y = -21 ⇒ (3)

- Add equation (1) and (3)

∴ 7y + 9y = 5 + -21

∴ 16y = -16

- Divide each side by 16

∴ y = -1

- Substitute the value of y in equation (1)

∴ 6x + 7(-1) = 5

∴ 6x - 7 = 5

- Add 7 to both sides

∴ 6x = 12

- Divide both sides by 6

∴ x = 2

* The solution is (2 , -1)