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24.05.2021 •
Mathematics
Which equation has no real solutions?
O A. 62 + 3b = -3
O B. 2c2 + 4c = 9
O C. -5c2 - C= -2
O D. 78 +1+3g2 = 0
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Ответ:
f(x)=(x+1)^2-2 is the minimum and g(x)=-(x-2)^2+1 is the maximum
Step-by-step explanation:
Looking at the graph, (you should be able to graph this) the parabola for f(x)=(x+1)^2-2 is pointing downwards and stops at the vertex. This vertex is negative which is the lowest point possible which makes it the minimum. The parabola for -(x-2)^2+1 is pointing upwards and stops at the vertex which is the highest point possible which makes it the maximum.