Which equation is equivalent to log3(2x4 + 8x3) – 3log3x = 2log3x? log3(–x3 + 8x2) = log3x2 –2log3(2x4 + 8x3 – x) = log3x2 log3(2x + 8) = log3x2 (the 3 after the log is the base)

This is the concept of algebra, to get the alternative form of the log expression below we simplified it as follows;

log3(2x^4+8x^3)-3log3x=2log3x
simplifying the above we get:
log3(2x^4+8x^3)=2log3x+3log3x
log3(2x^4+8x^3)=5log2x

Hence he answer should be:
log3 (x³)*(log3(2x+8))=5log3 x
3log3 x+log3(2x+8)=5log3 x
log3(2x+8)=5log3 x-3log3 x
log3 (2x+8)=2log3 x
log3 (2x+8)=log3 x²
the answer is log3 (2x+8)=log3 x²

1/2 plus 3/8 equals 7/8 Hope this helps!!