Which inequality is equivalent to [tex]3+ \frac{4}{x}

Ответ:

yialefi

12.03.2022

First, take all expressions to one side of the inequality:

$\displaystyle{ 3+\frac{4}{x}- \frac{x+2}{x} \geq 0$ .

Multiply 3 by $\displaystyle{ \frac{x}{x}$ to write it as a fraction with denominator equal to the other expressions

$\displaystyle{ \frac{3x}{x}+\frac{4}{x}- \frac{x+2}{x} \geq 0$ .

Since all three expressions have equal denominator, we collect them into one rational expression as follows:

$\displaystyle{ \frac{3x+4-x-2}{x}$ , which is equal to $\displaystyle{ \frac{2x+2}{x}$ .

Thus the inequality is $\displaystyle{ \frac{2x+2}{x} \geq 0$ .

A

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Ответ:

krystianah

12.04.2021

Mathematics

26.) 3(2)² - 8(-3)²

= 3*4 - 8 + 9

= 12 - 8 + 9 = 13

27.) I 7 - 4(2) I

7 - 8 = -1, but since this is absolute value, which is a number's distance from zero, your answer for 27 would be a positive one.

28.) (-2)² + 2(-3 * 1)

= 4 + 2(-3)

= 4 + (-6) = 4 - 6 = -2

29.) 7(-4)² + 5 / 4(1) - (-5)

=7 * 16 + 5 / 4 + 5

= 112 + 5 / 9 = 117/9 = 13

30.) Product: the result of a multiplication problem

Increased by: multiplied by

3(n * 7)

31.) 2n - 1

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Which inequality is equivalent to $3+ \frac{4}{x} \geq \frac{x+2}{x}$ ? a $\frac{2x+2}{x} \geq 0$ b $\frac{2x+6}{x} \geq 0$ c $\frac{-x+5}{x} \geq 0$ d $\frac{-x+9}{x} \geq 0$ show work and explain. i legitimately want to understand how to solve a question like this. you!

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Which inequality is equivalent to ﻿ ? a b cd show work and explain. i legitimately want to understand how to solve a question like this. you!

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Which inequality is equivalent to $3+ \frac{4}{x} \geq \frac{x+2}{x}$ ? a $\frac{2x+2}{x} \geq 0$ b $\frac{2x+6}{x} \geq 0$ c $\frac{-x+5}{x} \geq 0$ d $\frac{-x+9}{x} \geq 0$ show work and explain. i legitimately want to understand how to solve a question like this. you!