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shoafmckenzie5263
27.03.2020 •
Mathematics
Which is a solution of the inequality
-3x + 2 <5?
Solved
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Ответ:
Subtract 2 from both sides.
-3x less than 3
Divide both sides by -3
When you divide by a negative in an inequality the sign flips
x greater than -1
If you have any questions let me know. :)
Ответ:
f(x) = (x + 1)/ (6x^2 - 7x - 3)
= (x + 1)( / (6x^2 + 2x - 9x - 3)
= (x + 1) / (2x(3x + 1) - 3(3x + 1))
= (x + 1) / (2x - 3)(3x + 1)
Now x = 3/2 and x = -1/3 both make te denominator zero so these are both asymptotes.
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Step-by-step explanation: