Which locations have the smallest difference in elevation? location elevation (m) st. peter's square, vatican city state 33 laguna salada, mexico –10 chott melrhir, algeria −40 dniester, moldova 2 a. st. peter's square, vatican city state and dniester, moldova b. laguna salada, mexico and chott melrhir, algeria c. laguna salada, mexico and dniester, moldova d. st. peter's square, vatican city state and laguna salada, mexico

Vatican City:33
Mexico:-10
Algeria:-40
Moldova:2

we find the order them and find the distance betwen each
negatives are smallest
the bigger the negative, the smaller it is
so the order from smalles tot greatest is
-40,-10,2,33
find the difference by subtraction then take the absolute value (make the answer positive because distance is positive)
-40-(-10)=-40+10=-30 make positive and get 30

-10-2=-12 make positive and get 12

2-33=-31 make positive ang get 31

so the distances are
-40 to -10=30
-10 to 2=12
2 to 33=31

the smallest umber is 12

therefor the answer is between -10 and 2 which are the citys Laguna Salada, Mexico and Dniester, Moldova

the answer is C

when a=4 and b=3,

3.14((4 x 2)+ (4 x 3)) = 3.14(8+12) = 3.14 x 20 = 62.8