Which of the following polynomials has solutions that are not real numbers?

Assuming this question associates "solutions" with "zeros", then the answer is

   x^2 + 2x + 3 



If we set x^2 + 2x + 3 to equal 0, we have

   x^2 + 2x + 3 = 0

The discriminant of this equation of the form ax² + bx + c = 0 is

   discriminant = b² - 4ac = 2^2 - 4(1)(3) = -8

The discriminant is negative, so there are no real solutions (the discriminant is under a square root in the quadratic equation; square root of a negative number is not a real number)
                       

okay so

1.45 + 3.46 =  4.91

12.9 + 32.642= 45.542

101.00 + $42.00 = 143$ (united states U.S)

$20.25 - $10.15= 10.1$ (united states U.S)

34.005 - 11.9= 22.105

9.0007 -0.0009= 8.9998

Step-by-step explanation:

    I do not think i wanna explain step by step but i did hope this helps you i worked hard and sis this all my hand in paper but its not letting me upload it for proof but hope it helps.