Which statement is true? A rational number must show repeating digits after the decima
A rational number must show terminating digits after the decimal
An irrational number cannot be written as a repeating decimal.
An irrational number may show terminating digits after the decimal

An irrational number may show terminating digits after the decimal

Step-by-step explanation:

Examples of Rational Numbers

Number 9 can be written as 9/1 where 9 and 1 both are integers.  0.5 can be written as ½, 5/10 or 10/20 and in the form of all termination decimals.  √81 is a rational number, as it can be simplified to 9 and can be expressed as 9/1.  0.7777777 is recurring decimals and is a rational number

Examples of Irrational Numbers

Similarly, as we have already defined that irrational numbers cannot be expressed in fraction or ratio form, let us understand the concepts with few examples.

5/0 is an irrational number, with the denominator as zero.

π is an irrational number which has value 3.142…and is a never-ending and non-repeating number.

√2 is an irrational number, as it cannot be simplified.

0.212112111…is a rational number as it is non-recurring and non-terminating.

There are a lot more examples apart from above-given examples, which differentiate rational numbers and irrational numbers.

Properties of Rational and Irrational Numbers

Here are some rules based on arithmetic operations such as addition and multiplication performed on the rational number and irrational number.

#Rule 1: The sum of two rational numbers is also rational.

Example: 1/2 + 1/3 = (3+2)/6 = 5/6

#Rule 2: The product of two rational number is rational.

Example: 1/2 x 1/3 = 1/6

#Rule 3: The sum of two irrational numbers is not always irrational.

Example: √2+√2 = 2√2 is irrational

2+2√5+(-2√5) = 2  is rational

#Rule 4: The product of two irrational numbers is not always irrational.

Example: √2 x √3 = √6 (Irrational)

√2 x √2 = √4 = 2 (Rational)

P(2) = 4

Step-by-step explanation:

P(X) = -2X4 + 4X3 - X + 6

Use the remainder theorem to find quotient and remainder and the value of P(2)

First add in any missing exponents:  P(x) = -2x4 + 4x3 + 0x2 -x + 6

Write all the coefficients in a line (including the constant) with the number being solved for off to the left:

Bring down the first coefficient (-2), multiply it by the term in question (2), carry the product up under

the 2nd coefficient and then add down (4-4=0), carry up the sum and repeat process across.  The last

sum is the answer for P(2)

(2)   -2    4    0    -1    6

            -4    0      0  -2

       -2   0    0     -1   4

P(2) = 4

check the  P(2) = -2(24) + 4(23) -2 + 6 = -2(16) +4(8) + 4 = 4    Our answer is correct

The quotient is what we would bet by dividing the original equation by the polynomial (x-2). The

answer is given by the bottom numbers which will begin an one lower exponent than the original.

Quotient is:   -2x3 + 0x2 + 0x -1 = 2x3 - 1

The remainder is:   4/(x-2)