daedae96
20.12.2020 •
Mathematics
WILL GIVE BRAINLIESt:
Given: ∆ABC, AC = 5
m∠C = 90°
m∠A = 22°
Find: Perimeter of ∆ABC
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Ответ:
Perimeter of ΔABC is 12.41 units.
From the picture attached,
ΔABC is a right trianglem(AC) = 5 unitsm(∠C) = 90°m∠A = 22°Since, cosθ =
and sinθ = 
For angle A,
Adjacent side = AC = 5 units
Opposite side = BC
and Hypotenuse = AB
By substituting the values in the cosine ratio,
cos(22°) =
AB =
= 5.39
Since, sinθ =
sin(22°) =
BC = 5.39[sin(22°)]
= 2.02
Since perimeter of the given triangle ABC = AB + BC + AC
By substituting the measures of all sides in the expression of the perimeter,
Perimeter = 5.39 + 2.02 + 5
= 12.41 units.
Therefore, perimeter of the given triangle is 12.41 units.
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Ответ:
26m
Step-by-step explanation:
a^2+b^2=c^2
24^2+10^2=c^
576+100=c^2
676=c^2
√676=√c^2
26=c