Mathematics: Write a quadratic equation in standard form with intergral coefficeints that has the roots 4 and -5.

Write a quadratic equation in standard form with

Ответ:

katelynzaro

06.02.2022

$the \: quadratic \: equation \: is \to \: \\ \boxed{{x}^{2} + \: x \: -20 = 0}.$

Step-by-step explanation:

$the \: general \: sandard \: form \: is \: given \: by : \\ ax {}^{2} + bx + c = 0 \to \\ since \: the \: roots \: are : \\ 4 \: and \: - 5 \\ we \: apply \: the \: rule \to \\ {x}^{2} - ( \alpha + \beta )x \: + \alpha \beta = 0 \\ therefore \: \to \\ {x}^{2} - ( 4+ ( - 5) )x \: + 4( - 5) = 0 \\ {x}^{2} + \: x \: -20 = 0.$

♨Rage♨

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Ответ:

larahanna

21.12.2020

Mathematics

Hi!

$6\sqrt{-*20}$

6*20=120

$=120\sqrt{-}$

Explanation: You had to multiply 6*20=120. And the answer is 120√- is the right answer. Hope this helps! And thank you for posting at here on And have a great day. -Charlie

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Write a quadratic equation in standard form with intergral coefficeints that has the roots 4 and -5.

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