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liz77717
25.09.2020 •
Mathematics
Write an equation of the line passing through the point (5, 1) that is perpendicular to the line 5x+3y=15.
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Ответ:
Here, we are required to Write an equation of the line passing through the point (5, 1) that is perpendicular to the line 5x+3y=15.
The equation of the line is; 3x - 5y = 10.
By comparison with the equation of a straight line: y = Mx + c
The equation 5x+3y=15 can be rewritten as ;
y = (-5/3)x + 5
Therefore, the slope of the equation is; (-5/3)
The product of the slope of two perpendicular lines is: -1.
therefore m1m2 = -1
Therefore; M2 = -1/(-5/3)
Therefore M2 = 3/5
The equation of the line passing through the point (5, 1) that has slope, M2 = 3/5 is;
3/5 = (y - 1)/(x - 5)
By Cross product;
3x - 15 = 5y -5
Therefore, the equation of the line is;
3x - 5y = 10.
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Ответ:
y =
x - 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
5x + 3y = 15 ( subtract 5x from both sides )
3y = - 5x + 15 ( divide all terms by 3 )
y = -
x + 5 ← in slope- intercept form
with slope m = -![\frac{5}{3}](/tpl/images/0780/2554/dcb5a.png)
Given a line with slope m then the slope of a line perpendicular to it is
y =
x + c ← is the partial equation
To find c substitute (5, 1) into the partial equation
1 = 3 + c ⇒ c = 1 - 3 = - 2
y =
x - 2 ← equation of perpendicular line
Ответ:
2d^2ef^4/3 (its a fraction. 3 is on the bottom, 2d^2ef^4 is on the top)
Step-by-step explanation:
this is simplifying the expression getting the quotient. hope this helps.