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TrueKing184
18.08.2019 •
Mathematics
Write an equation of the line that is:
a) parallel to the line y=2x-4, and has a y-intercept of 7
b) parallel to the line y-3x=6, and has a y-intercept of -2
c) parallel to the line 2x+3y=12, and that passes through the origin
d) perpendicular to the line y=3x+2, and has a y-intercept of 2
e) perpendicular to the line 3y+4x=18, and that passes through the origin
answer all these question
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Ответ:
(a) parallel to the line y=2x-4, and has a y-intercept of 7
slope of first line: 2
slope of second line: 2
y=mx + b
y=2x+7
(b) parallel to the line y-3x=6, and has a y-intercept of -2
y=3x+6
slope of first line: 3
slope of second line: 3
y=mx + b
y=3x-2
(c) parallel to the line 2x+3y=12, and that passes through the origin
3y=-2x+12
y=-2/3x+4
slope of first line: -2/3
slope of second line: -2/3
origin: (0,0)
y=mx + b
y=-2/3x + 0
y=-2/3x
(d) perpendicular to the line y=3x+2, and has a y-intercept of 2
slope of first line: 3
slope of second line: -1/3
y=mx + b
y=-1/3x + 2
(e) perpendicular to the line 3y+4x=18, and that passes through the origin
3y=4x+18
y=4/3x+6
slope of first line: 4/3
slope of second line: -3/4
origin: (0,0)
y=mx + b
y=-3/4x + 0
y=-3/4x
Ответ:
-67
Step-by-step explanation:
x=-6
-6^2+6(-6)+5
pls