Mathematics: Write an equation that is perpendicular to the line y = 5x + 3 that contains point A(0,7).

B. So just go up from -2 :D -1, 0, 1, 2....

Write an equation that is perpendicular to the line

googoo4

14.02.2022

$y=\dfrac{-x}{5}+2$

Step-by-step explanation:

The given equation of line :

y = 5x + 3 ....(1)

The general equation of a line is :

y = mx +b ...(2)

From equation (1) and (2)

Slope, m = 5

The slope of the line perpendicular to this one will have a slope equal to the negative reciprocal such that,

$m_1\times m_2=-1\\\\m_2=-\dfrac{1}{5}$

The perpendicular slope = -1/5. It contains point A(0,7).

Put x = 0 and y = 7 in eqution (2)

$2=(\dfrac{-1}{5})(0)+b\\\\b=2$

Hence, required equation that is perpendicular to the line y = 5x + 3 is :

$y=\dfrac{-x}{5}+2$

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