mahmudabiazp3ekot
29.08.2019 •
Mathematics
Write the equation of the line that is perpendicular to the line x-3y=2 and passes through the point (0,4).
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Ответ:
-3y = -x + 2
y = (-1/3)x - 2/3
perp.: 3
y - 4 = 3(x - 0)
y - 4 = 3x - 0
y= 3x + 4
Ответ:
or (5.5,5)
Step-by-step explanation:
midpoint formula :
where (x1,y1) and (x2,y2) are the two given points.
We want to find the midpoint of A and B where A has coordinates of (8,2) and B has coordinates of (3,8)
To do so we simply plug in the x and y values of the coordinates into the formula
Note that (x1,y1) = (8,2) so x1 = 8 and y1 = 2
and
(x2,y2) = (3,8) so x2 = 3 and y2 = 8
Recall the midpoint formula
We have x1 = 8, y1 = 2, x2 = 3 , y2 = 8
* plug in values into formula *
add 8 and 3 , and 2 and 8
reduce fractions
The midpoint would be at (11/2,5) or (5.5,5)