ricardorendon100
01.07.2019 •
Mathematics
Write the following equation in standard form: 2/3 a+5a^3 +4a^4 -2a^5
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Ответ:
-2a^5+4a^4+5a^3+2/3a apex
Step-by-step explanation:
Ответ:
Given that:
TanФ = 5√11/11
Using SOH CAH TOA
Sin Ф = opp/hyp
CosФ = adj/hyp
TanФ = opp/adj
Therefore,
From the given identity we can say that:
Opposite = 5√11
Adjacent = 11
Using Pythagoras formula:
a² + b² = c²
Where c is the hypotenuse, a and b are the opposite and adjacent.
We can now find the hypotenuse.
(5√11)² + 11² = c²
(25 × 11) + 121 = c²
275 + 121 = c²
396 = c²
Taking square root on both sides,
we get:
c = √396
c = 6√11
Now, we have all the three sides and again using SOH CAH TOA, we can figure out the exact value of Sin Ф.
Sin Ф = Opp/Hyp
Sin Ф =5√11 /6√11
Canceling the like terms,
we get:
Sin Ф =5/6
Now, we know that, in the third quadrant, only TanФ is positive and the rest of the trigonometric values are negative, we will have the negative value of the opposite side.
Hence,
Sin Ф = - 5/6