Xavier is two years more than twice as old as yoko. the sum of their ages is 86. how old is xavier?

The equation for this would be X+2X+2= 86, because X is yoko's age which is half the age pf Xavier hence the 2X plus two more years hence + 2. Now we combine like numbers so the equation becomes 3X+2=86. Now it's a simple alhebra question. Subtract 2 from both sides to get 3X=84. Finally divide 3 from both sides 84 divided by 3 is 28 so Yoko is 28. Using Order of operations we know to multiply 28 by 2 to get 56. Now add two to get 58.Make sure this is right by plugging those into the equation and see if 58 28 which does equal 86 so Xavier is 58 years old

Subtract 2 from 86 and then divide that by 2. Add the 2 back in and you get Xavier's age. The answer is 44.

1107.

You are rounding up because the number in the tenths slot is over 5.