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ktyree100
28.07.2019 •
Mathematics
You invested 29,000 in two accounts paying 6% and 8% annual interest, respectively. if the total interest earned for the year is $2060, how much was invested at each rate
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Ответ:
0.06x + 0.08y = 2060 (interest)
x + y = 29,000 (money invested)
Multiply each term in the second equation by -0.06 to cancel out the 0.06x from the first equation.
-0.06x - 0.06y = -1740
Now add this equation to the first equation and solve for y.
0.06x + 0.08y = 2060
-0.06x - 0.06y = -1740
0.02y = 320
y = 16,000
Since you know y = 16,000 you can substitute it into either of the original equations to solve for x. I picked the second equation because it's simpler, but you could also use the first.
x + 16,000 = 29,000
x = 13,000
So you invested 16,000 at 8% and 13,000 at 6%.
Ответ:
circumference = π2r = (3.14)(2)(21) = 131.88 miles
Step-by-step explanation: