Your iron works has been contracted to design and build a 500-ft3 square-based, open-top, rectangular steel holding tank for a paper company. the tank is to be made by welding half-inch-thick stainless steel plates together along their edges. as the production engineer, your job is to find dimensions for the base and height that will make the tank weight as little as possible. what dimensions do you tell the shop to use?

500 cubic feet of 1/2-inch thick stainless steel plates will weigh the same no matter what dimensions are use for area and height of tank.

A 5 foot by 5 foot area 20 feet high (500 cubic feet) will weigh just as much as a  10 foot by 10 foot area 5 feet high (also 500 cubic feet) since you are using the same amount of material for the whole tank. Only possible change in weight of tank is the use of welding material and how evenly and good the welder is at welding stainless steel.

The average of the next five quizzes = 83.

Step-by-step explanation:

Given : After taking 4 quizzes your average is 74 points out of 100.

Let q be the average of the next five quizzes.

Then , the total number of quizzes = 4+5=9

Since ,

Sum of observations = (Average) x (Number of observations)

i.e.  Sum of first four quizzes = 74 (4)

Sum of next five quizzes = 5q

According to the question , we have

Hence, the average of the next five quizzes = 83.