A 1.85 H inductor carries a steady current of 0.450 A. When the switch in the circuit is thrown open, the current is effectively zero in 10.0 ms. What is the average induced emf in the inductor during this time?

i

Induced emf will be equal to 83.25 volt

Explanation:

We have given value of inductance L = 1.85 H

Initially the current flow is equal to 0.450 A

When switch is open current become 0 in 10 ms

So change in current di = 0.450-0=0.450 A

Time taken to change the current dt = 10 ms = 0.01 sec

Induced emf is equal to

So

Induced emf will be equal to 83.25 volt

the first box is correct

The two dry sand samples are examined by changing one parameter. The independent variable, the one that is intentionally manipulated between the two samples, is the  Mass of each sample

the second box as well

Besides the amount of material, there is also another variable that is manipulated within each of the two mass groups and represented as three types. This independent variable is the type of material used

& the third box

In each case, the dependent variable, the one that you measure the response in, is the temperature over time