A 5kg book rests on a table. How much force is it exerting on the table?

The kind of spring needed to launch the 0.35 kg mug to 7 m high from start is 7510.78 N/m.

Explanation:

To solve the question, we note that the

Mass m of the mug = 350 g

Height to which mug is to be launched to = 7 m

Length of spring = 20 cm

Therefore we look for the governing equations of motion as follows

Energy required to raise the mug to 7 m = Gravitational Potential of the mug at 7 m and

Gravitational Potential = m·g·h

Where m = mass = 350 g = 0.35 kg

h = height = 7 m

g = Acceleration due to gravity = 9.81  m/s²

Energy of spring to raise the height of the mug to 7 m =

Where:

K = Spring constant

x = Length of compression or expansion

Equating the Energy supplied to the energy gained we get

m·g·h =

Making k the subject of the formula gives

= = 7510.78 N/m.