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Cannon2793
18.01.2021 •
Physics
A 6.00-kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the end of the rope, and the height of the crate above its initial position is given by y(t)=(2.80m/s)t+(0.610m/s^3)t^3. What is the magnitude of F when t = 4.00 s?
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Ответ:
The magnitude of F when t=4 s=146.64 N
Explanation:
We are given that
Mass of crate,m=6.00 kg
Height of crate above its initial position is given by
We have to find the magnitude of F when t=4.00 s
Differentiate w.r.t t
Now, magnitude of force
Hence, the magnitude of F when t=4 s=146.64 N
Ответ: