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whitakers87
17.06.2021 •
Physics
A car's speed changes from 10m/s to 35m/s in 15.0s along a straight road while moving in one way. Find the magnitude of the acceleration of the car during this period.
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Ответ:
1.67 m/s²
Explanation:
Applying,
a = (v-u)/t Equation 1
Where a = acceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.
From the question,
Given: v = 35 m/s, u = 10 m/s, t = 15.0 s
Substitute these values into equation 1
a = (35-10)/15
a = 25/15
a = 1.67 m/s²
Hence the acceleration of the car is 1.67 m/s²
Ответ:
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