sophie5988
26.03.2020 •
Physics
A circuit has a 2Ω resistor in series with a 4Ω resistor. What is the total resistance of the circuit?
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Ответ:
6Ω
Explanation:
Since the resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.
i.e Rtotal = R1 + R2
R1 = 2Ω
R2 = 4Ω
Rtotal = ?
Rtotal = 2Ω + 4Ω
Rtotal = 6Ω
Thus, the total resistance of the circuit is 6Ω
Ответ:
i don't understand the hw