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FlowerChild5037
07.04.2020 •
Physics
A closely wound search coil has an area of 3.12 cm2cm2 , 135 turns, and a resistance of 58.8 ΩΩ . It is connected to a charge-measuring instrument whose resistance is 43.4 ΩΩ . When the coil is rotated quickly from a position parallel to a uniform magnetic field to one perpendicular to the field, the instrument indicates a charge of 3.46×10−5 CC
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Ответ:
B = 0.08395 T = 83.95 mT
Explanation:
According to the Faraday's law of electromagnetic induction, the induced emf is given as
E = -N (dΦ/dt)
The minus sign indicates that the emf is induced in a direction opposite to the changing magnetic flux.
Magnitude of emf is
E = N (dΦ/dt)
From Ohm's law
E = IR
But I = (dQ/dt)
E = R (dQ/dt)
N (dΦ/dt) = R (dQ/dt)
N dΦ = R dQ
Integrating both sides,
NΦ = RQ
But, Φ = BA
N BA = RQ
B = (RQ/NA)
R = 58.8 + 43.4 = 102.2 Ω
Q = (3.46×10⁻⁵) C
A = 3.12 cm² = (3.12 × 10⁻⁴) m²
N = 135
B = (102.2 × 3.46×10⁻⁵)/(135 × 3.12 × 10⁻⁴)
B = 0.0839534663 T = 0.08395 T = 83.95 mT
Hope this Helps!!!
Ответ:
23
Explanation: