A flashlight bulb is connected to a dry cell of voltage 2.25 V. It draws 35.0 mA (1000 mA = 1 A). What is its resistance?
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Ответ:
Explanation:
V = IR
2.25 V = (35.0 mA × 1 A / 1000 mA) R
2.25 V = (0.0350 A) R
R = 64.3 Ω
Ответ: