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beeboppity
14.04.2020 •
Physics
A football is kicked from ground level with an initial velocity of 23.4 m/s at angle of 33.5° above the horizontal. How long, in seconds, is the football in the air before it hits the ground? Ignore air resistance.
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Ответ:
4.16 seconds
Explanation:
Data:
Acceleration a = -9.8 m/s²
Initial velocity 'vi' = 23.4m/s
as the ball traveled up and eventually came back down to the same level, the vertical distance y traveled by the football is zero.
therefore, y = 0
next is to find the vertical velocity of the football.
We need to find the speed of the ball immediately after it is kicked.
So, let it be represented by![v_{iy}](/tpl/images/0599/6144/1e0de.png)
by the help of kinematic equation i.e d =
t + 0.5* (at²)
, we'll figure out time't'
The distance 'd' would be zero as it is the vertical distance.
Putting the values in above equation, it becomes
0 = 20.38*t + 0.5* (-9.8* t²)
0 = t(20.38 - 4.9t)
20.38 = 4.9t
20.38/4.9 = t
t = 4.16 seconds
Before the football hits the ground,it was in the air for 4.16 seconds
Ответ: