Physics: A long, straight wire carrying a current of 245 A is placed in a uniform magnetic field that has a magnitude of 6.40 10-3 T. The wire is perpendicular to the field. Find a point in space where the net magnetic field is zero. Locate this point by specifying its perpendicular distance from the wire.

A long, straight wire carrying a current of 245

kyle65

23.01.2022

0.076 m

Explanation:

Given,

Current in the wire,I = 245 A

Magnetic field, B = 6.40 x 10⁻³ T

perpendicular distance,r = ?

Using magnetic field formula

$B=\dfrac{\mu_0 I}{2\pi r}$

$r=\dfrac{\mu_0 NI}{2\pi B}$

$r=\dfrac{4\pi\times 10^{-7}\times 245}{2\pi \times 6.40 \times 10^{-3}}$

r = 0.076 m

Hence, Perpendicular distance from the wire is equal to 0.076 m

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amanda2517

07.03.2022

Travelled 21.84m

Explanation:

5.6 metres a second, 3.9 seconds.

5.6×3.9=21.84

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