A machine part rotates at an angular speed of 0.76 rad/s; its speed is then increased to 2.96 rad/s using an angular acceleration of 1 rad/s 2 . Find the angle through which the part rotates before reaching this final speed. Answer in units of rad.
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Ответ:
θ = 4.092 °
Explanation:
Given that
Initial Angular speed ,ωi = 0.76 rad/s
Final angular speed ,ωf= 2.96 rad/s
The angular acceleration ,α = 1 rad/s²
We know that
ωf² = ωi ²+ 2 α θ
θ=Angle rotates
2.96² = 0.76²+ 2 x 1 x θ
Therefore the angle rotates by machine part will be 4.092 degrees.
θ = 4.092 °
Ответ: