.A millimeter cube of carbon the size of a pencil point contains about 77 coulombs of positive and negative charge. If you could separate all of the positive and negative charges by a distance of one meter the attractive force between them would be about

Explanation:

The magnitude of the electricforce between two charges is given by the formula:

where:

is the Coulomb's constant

are the two charges

r is the separation between the two charges

And the force is:

- Repulsive if the two charges have same sign

- Attractive if the two charges have opposite sign

In this problem, we have:

is the magnitude of the positive charge

is the magnitude of the negative charge

r = 1 m is the distance between the two charges

So, the magnitude of the electrostatic force is

-150 N

Explanation:

(Newton's second law) F=ma

Sum of forces in Y direction= (+200 N)+(-200 N)= 0...

forces cancel, object does not accelerate up/down

Sum of forces in X direction= (+65 N)+(-65 N)+(-150 N)

= -150 N

notice that the +/- 65 components cancel, leaving a net force of 150 N in the LEFTwards direction (which is typically defined as negative)

Overall, the net force is -150 N