A placekicker kicks a football at and angle of 40.0 degrees and the initial speed of the ball is 22 m/s. Ignoring air resistance, determine the maximum height that the ball attains.

The maximum height attains by ball is 48.64 meter.

The maximum height is given by using formula,

                 

Where u is initial velocity, and value of

Given that,  

Substituting above values in formula.

             

Hence, the maximum height attains by ball is 48.64 meter.

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10.18m

Explanation:

in this problem, we are expected to solve for the maximum height of a projectile (the ball)

Firstly, the expression for maximum height is

h = u ^2 *sin ^2 θ /2 g

Given data

initial velocity u=22m/s

angle of projection, θ= 40degrees

substituting into the expression we have

h = 22^2 *sin (40)^2 /2 *9.81

h = 484*0.413 /19.62

h =199.892 /19.62

h=10.18m

The maximum height is 10.18m

K(x) = (1/4)^x

(1,4) when x = 1, k(1) = (1/4)^1 = 1/4FALSE
(3, 1/64) when x = 3, k(3) = (1/4)^3 = 1/64TRUE
(-1,4) when x = -1, k(-1) = (1/4)^-1 = 4TRUE
(0, 1/4) when x = 0, k(0) = (1/4)^0 = 1FALSE

answer
(3, 1/64)
(-1,4)