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ramirez5571
13.02.2020 •
Physics
A rock is tossed straight up from ground level with a speed of 22 m/s. When it returns, it falls into a hole 9.0 m deep. a. What is the rock’s velocity as it hits the bottom of the hole? b. How long is the rock in the air, from the instant it is released until it hits the bottom of the hole?
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Ответ:
(a)![v_{f}=26.08m/s](/tpl/images/0509/4752/d0612.png)
(b)![t=4.906seconds](/tpl/images/0509/4752/edbe8.png)
Explanation:
We will take ground level as origin and upward is positive direction
the givens are
Part (a)
To find the final velocity we use the kinematic equation
So
Part (b)
To find time of rock trip until it touches the ground we will use simple kinematic equation or simple motion equation
Notice that we substituted vf with negative sign because its direction is downwards
Ответ:
D
Explanation: